pyspark.pandas.Series.transform#
- Series.transform(func, axis=0, *args, **kwargs)[source]#
Call
func
producing the same type as self with transformed values and that has the same axis length as input.Note
this API executes the function once to infer the type which is potentially expensive, for instance, when the dataset is created after aggregations or sorting.
To avoid this, specify return type in
func
, for instance, as below:>>> def square(x) -> np.int32: ... return x ** 2
pandas-on-Spark uses return type hint and does not try to infer the type.
- Parameters
- funcfunction or list
A function or a list of functions to use for transforming the data.
- axisint, default 0 or ‘index’
Can only be set to 0 now.
- *args
Positional arguments to pass to func.
- **kwargs
Keyword arguments to pass to func.
- Returns
- An instance of the same type with self that must have the same length as input.
See also
Series.aggregate
Only perform aggregating type operations.
Series.apply
Invoke function on Series.
DataFrame.transform
The equivalent function for DataFrame.
Examples
>>> s = ps.Series(range(3)) >>> s 0 0 1 1 2 2 dtype: int64
>>> def sqrt(x) -> float: ... return np.sqrt(x) >>> s.transform(sqrt) 0 0.000000 1 1.000000 2 1.414214 dtype: float64
Even though the resulting instance must have the same length as the input, it is possible to provide several input functions:
>>> def exp(x) -> float: ... return np.exp(x) >>> s.transform([sqrt, exp]) sqrt exp 0 0.000000 1.000000 1 1.000000 2.718282 2 1.414214 7.389056
You can omit the type hint and let pandas-on-Spark infer its type.
>>> s.transform([np.sqrt, np.exp]) sqrt exp 0 0.000000 1.000000 1 1.000000 2.718282 2 1.414214 7.389056